Friday, April 30, 2010

GRE Math Problem 72

Compare two values:
Column A Column B
The average (arithmetic mean) of all the positive multiples of 5 less than 26 The average (arithmetic mea: of all the positive multiples of 7 less than 26

Tuesday, April 27, 2010

Solution for Questions GRE Analytical Problem 5, Part 2


Question IV
If S appears on a panel, that panel must consist of at least how many professors?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7

C6: S => (NV)
And there are no more conditions that require more members.
Answer (A) 3

Question V
Which of the following is an acceptable group of professors for a panel?
(A) M, N, Q, R – violates C2: !(MNR)
(B) M, Q, R,T – is quite acceptable
(C) M, R, T, U  – violates C5: R <=> Q
(D) M, S, U, V – violates C6: S => (NV)
(E) N,R,T,U – violates C5: R <=> Q
Answer (A) M, N, Q, R

Question VI
Which of the following groups of professors can form an acceptable panel by doing nothing more than adding one more professor to the group?
(A) M, R, T
C5:R <=> Q
We must add Q and we’ll get an acceptable panel

(B) N,Q,M
C5:R <=> Q
We must add R/ But that panel would violate
C2: !(MNR)

(C) Q,R, S
According to
C6: S => (NV)
We must add both N and V

(D) Q,R,V
C4: V=>(MS) or (MU) or (SU) or (MSU)
We must add at least two members

(E) V, R, N
C4: V=>(MS) or (MU) or (SU) or (MSU)
We must add at least two members

Answer (A) M, R, T

Question VII
Of the group N, S, T, U, V, which professor will have to be removed to form an acceptable panel?
(A) N
(B) S
(C) T
(D) U
(E) V

This panel violates
C1:!(NTU)
So, we must remove one of them.

But the presence of N and V is required by S
C6: S => (NV)
Then, we must remove T

Answer (C) T

Monday, April 26, 2010

Solution for Questions GRE Analytical Problem 5, Part 1

Solution for Questions GRE Analytical Problem 5:

Let’s fix the conditions:
C1: N, T, and U cannot all appear on the same panel.
!(NTU)
In another form it can be written:
(NT)=>!V
(NU)=>!T
(TU)=>!N

C2: M. N, and R cannot all appear on the same panel.
!(MNR)
In another form it can be written:
(MN)=>!R
(MR)=>!N
(NR)=>!M

C3: Q and V cannot appear on the same panel.
!(QV)
In another form it can be written:
Q <=> !V
V <=> !Q

C4: If V appears on a panel, at least two professors of the trio M, S, and U must also appear on the panel.
V=>(MS) or (MU) or (SU) or (MSU)
Or, equivalent to this:
(!M!S) or (!M!U) or (!S!U)=>!V

C5: Neither R nor Q can appear on a panel unless the other also appears on the panel.
R <=> Q
From this follows:
!R <=> !Q

C6: If S appears on a panel, both N and V must also appear on that panel.
S => (NV)
Then,
!N or !V => !S

Now we can proceed to question solving.

Question I
Which of the following CANNOT appear on a panel with R?
(A) M
(B) N
(C) Q
(D) S
(E) T

C5: R <=> Q
C4: Q <=> !V
C6: !N or !V => !S

So, professor S CANNOT appear on a panel with R
Answer (D) S

Question II
Exactly how many of the professors can appear on a panel alone?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

C4: V=>(MS) or (MU) or (SU) or (MSU)
Professor V can’t appear on a panel alone.

C5: R <=> Q
Professor’s R and Q can’t appear on a panel alone.

C6: S => (NV)
Professor S can’t appear on a panel alone.

So, only four of them can.
Answer (D) 4

Question III
If neither V nor N appears on a panel, then which of the following must be true?
(A) M appears on the panel.
(B) Q appears on the panel.
(C) T appears on the panel.
(D) S does not appear on the panel.
(E) U does not appear on the panel.

C6: !N or !V => !S
Answer (D) S does not appear on the panel.

Monday, April 19, 2010

Analytical Problem 5




The planning committee of an academic conference is planning a series of panels using eight professors, M, N, Q, R, S, T, U, and V. Each panel must be put together in accordance with the following conditions:

N, T, and U cannot all appear on the same panel.
M. N, and R cannot all appear on the same panel.
Q and V cannot appear on the same panel.
If V appears on a panel, at least two professors of the trio M, S, and U must also appear on the panel.
Neither R nor Q can appear on a panel unless the other also appears on the panel.
If S appears on a panel, both N and V must also appear on that panel.

Question I
Which of the following CANNOT appear on a panel with R?
(A) M
(B) N
(C) Q
(D) S
(E) T

Question II

Exactly how many of the professors can appear on a panel alone?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Question III
If neither V nor N appears on a panel, then which of the following must be true?
(A) M appears on the panel.
(B) Q appears on the panel.
(C) T appears on the panel.
(D) S does not appear on the panel.
(E) U does not appear on the panel.

Question IV
If S appears on a panel, that panel must consist of at least how many professors?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7

Question V
Which of the following is an acceptable group of professors for a panel?
(A) M, N, Q, R
(B) M, Q, R,T
(C) M, R, T, U
(D) M, S, U, V
(E) N,R,T,U

Question VI
Which of the following groups of professors can form an acceptable panel by doing nothing more than adding one more professor to the group?
(A) M, R, T
(B) N,Q,M
(C) Q,R, S
(D) Q,R,V
(E) V, R, N

Question VII
Of the group N, S, T, U, V, which professor will have to be removed to form an acceptable panel?
(A) N
(B) S
(C) T
(D) U
(E) V




Solution for GRE Math Problem 71:

Peter's grade > Victor's grade
Georgette’s grade > Victor's grade

We can’t determine, which of these grades is higher

Answer:D

Tuesday, April 13, 2010

GRE Math Problem 71

Peter's grade was higher than that of Victor.and Victor's grade was less than that of Georgette.


Column A Column B
Georgette's grade Peter's grade


Solution for GRE Math Problem 70:



Area=length x width

New Area=length x (1.25 width) = 1.25 (length x width) = 1.25 Area

Area will increase by 25%.


Answer:(A) 25%

Monday, April 12, 2010

GRE Math Problem 70

If the width of a rectangle is increased by 25% while the length remains constant, the resulting area is what percent of the original area?
(A) 25% 
(B)75% 
(C) 125% 
(D)225%
(E) Cannot be determined from the information given.


Solution for GRE Math Problem 69:

At what rate is the water filling the tank?
800-300=500 cubic feet
How many minutes will it take to completely fill a water tank?
3,750:500 = 7.5 minutes = 7 min. 30 sec.

Answer:(C) 7 min. 30 sec.

Sunday, April 11, 2010

GRE Math Problem 69



How many minutes will it take to completely fill a water tank with a capacity of 3,750 cubic feet if the water is being pumped into the tank at the rate of 800 cubic feet per minute and is being drained out of the tank at the rate of 300 cubic feet per minute?
(A) 3 min. 36 sec.
(B) 6 minutes
(C) 7 min. 30 sec.
(D) 8 minutes
(E) 1,875 minutes


Solution for GRE Math Problem 68:

The legs of triangle BCE equal to the sides of the square ABCD. So, its area is the half of the area of ABCD. Thus,  the area of ABCD is 16


Answer:(C) 16

Saturday, April 10, 2010

GRE Math Problem 68


 If the area of the triangle BCE is 8, what is the area of the square ABCD?
(A) 4
(B) 8
(C) 16
(D) 22
(E) 82


Solution for GRE Math Problem 67:
As and , then PQRS is a parallelogram. And as PQ=QR, it is a rhomb. Its obtuse angle equals 120 degrees, and the acute angle is 60 degrees. Then, triangle PQR is equilateral and PQ=QR=QP=3
Answer: (C) 3

Friday, April 9, 2010

GRE Math Problem 67



Here and .
If PQ=3 and QR=3, then what is the length of PR?
(A)
(B)
(C) 3
(D)
(E)



Solution for GRE Math Problem 66:
As the y-coordinates of A and B are equal, the distance between them is 2-(-4)=6. That’ll be the diameter of the circle. The radius of the circle is 3. Its area will be
Answer:(C) 9

Thursday, April 8, 2010

GRE Math Problem 66

If A is the point (-4, 1) and B is the point (2, 1), what is the area of the circle which has AB as a diameter?
(A) 3
(B) 6
(C) 9
(D) 12
(E) 36


Solution for GRE Math Problem 65:


1 < ab < 2
2 < a+b < 4

So, ab < 2 < a+b


Answer:B

Wednesday, April 7, 2010

GRE Math Problem 65

a < b

Column A Column B
ab a+b

Solution for GRE Math Problem 64:



As we can see, the circle whose diameter is a is located within the square whose side is a for any value of a. So, the square’s area is greater.


Answer: A

Tuesday, April 6, 2010

GRE Math Problem 64

a<1

Column A Column B
The area of a square whose side is a The area of a circle whose diameter is a

Solution for GRE Math Problem 63:
As

then



Let’s find the difference

Then c

Answer:B

Monday, April 5, 2010

GRE Math Problem 63

c and d are positive


Column A Column B
c d


Solution for GRE Math Problem 62:
Point (a,b) lays in the quarter where x<0 and y>0. So, a<0 and b>0 and b>a
Answer:B

Sunday, April 4, 2010

GRE Math Problem 62



Column A Column B
a b


Solution for GRE Math Problem 61:
326(31)-326(19) =326(31-19)=326(12) – here we need not make any calculations, because there is only one answer which is more than 10 times greater than 326

Answer:(A)3,912

Saturday, April 3, 2010

GRE Math Problem 61

326(31)-326(19) =
(A)3,912
(B)704
(C)100
(D)326
(E)10

Solution for GRE Math Problem 60:
  for x>0
Answer:B

Friday, April 2, 2010

GRE Math Problem 60

x>0


Column A Column B


Solution for GRE Math Problem 59:

The perimeter of the square is
 Answer:(C) 3x + 4

Thursday, April 1, 2010

GRE Math Problem 59

The length of each side of a square is
What is the perimeter of the square?
(A) x + 1
(B) 3x + 1
(C) 3x + 4
(D)
(E) It cannot be determined from the information given.

Solution for GRE Math Problem 58:

How much, in dollars, will receive the second one?
240-180 = 60

What is the difference between the amounts received by the two persons?
180-60=120

Answer: (C)$120