GRE Math Problem 65

a < b

Column A	Column B
ab	a+b

Solution for GRE Math Problem 64:

As we can see, the circle whose diameter is a is located within the square whose side is a for any value of a. So, the square’s area is greater.


Answer: A

GRE Math Problem 64

a<1

Column A	Column B
The area of a square whose side is a	The area of a circle whose diameter is a

Solution for GRE Math Problem 63:
As

then



Let’s find the difference

Then c

Answer:B

GRE Math Problem 63

c and d are positive

Column A	Column B
c	d

Solution for GRE Math Problem 62:
Point (a,b) lays in the quarter where x<0 and y>0. So, a<0 and b>0 and b>a
Answer:B

GRE Math Problem 62

Column A	Column B
a	b

Solution for GRE Math Problem 61:
326(31)-326(19) =326(31-19)=326(12) – here we need not make any calculations, because there is only one answer which is more than 10 times greater than 326

Answer:(A)3,912

GRE Math Problem 61

326(31)-326(19) =

(A)3,912

(B)704

(C)100

(D)326

(E)10

Solution for GRE Math Problem 60:
  for x>0
Answer:B

GRE Math Problem 60

x>0

Column A	Column B

Solution for GRE Math Problem 59:

The perimeter of the square is
 Answer:(C) 3x + 4

GRE Math Problem 59

The length of each side of a square is
What is the perimeter of the square?
(A) x + 1
(B) 3x + 1
(C) 3x + 4
(D)
(E) It cannot be determined from the information given.

Solution for GRE Math Problem 58:

How much, in dollars, will receive the second one?
240-180 = 60

What is the difference between the amounts received by the two persons?
180-60=120

Answer: (C)$120