Dr. William Weinberg is a psychiatrist who has to schedule one therapy session for each of six patients— Bernstein, Cox, Dawson, Edson, Friedman, and Grant. Each session will take place on the same day. The sessions will be scheduled at 9:00, 10:00, 11:00, 1:00, 2:00, and 3:00, with a lunch break at noon.
In making up the schedule for the session, Dr. Weinberg will conform to the following conditions:
- Friedman will have the first session in the afternoon.
- Bernstein's session must be earlier in the day than either Edson's or Friedman's.
- Cox's session must immediately precede Grant's session.
Question I. If Bernstein is only available at 10:00, in how many ways can the sessions be scheduled?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 6
Question II. If Friedman switches to a morning session, and Cox takes the 1:00 spot vacated by Friedman, which of the following must be true?
(A) Bernstein has the first session of the day.
(B) Bernstein or Friedman has the second session
of the day.
(C) Bernstein or Dawson has the second session of
the day.
(D) Dawson or Friedman has the third session of
the day.
(E) Dawson or Grant has the last session of the
day.
Question III. If Grant has the last session of the day, each of the following could be true EXCEPT
(A) Bernstein has the first session of the day.
(B) Dawson
(C) Dawson has his session at 10:00.
(D) Edson has her session at 10:00.
(E) Cox has his session at 2:00.
Question IV. If Cox's session is earlier in the day than Friedman's, which of the following must be true?
(A) Bernstein has the first session of the day.
(B) Cox has the first session of the day.
(C) Bernstein has a session at 11:00.
(D) Grant has a session at 11:00.
(E) Dawson
Solution for GRE Math Problem 4:
Number 2n has all the prive factors, which number n has. Additionaly, as number n is odd, prime number 2 is not among its prime factors, but number 2n has 2 among it prime factors. So, the number of prime factors of 2n is bigger than the number of prime factors of n.
Answer: B
Posts
No comments:
Post a Comment