(A) 3ac
(B) 3a+c
(C) 6a+c
(D) 9ac
(E) 9a+c
Solution for GRE Math Problem 41:
Let’s build this sequence: 1, 1x3-1=2, 2x3-1=5, 5x3-1=14, 14x3-1=41, 41x3-1=122 – this is the smallest term greater than 100. It is greater than 120
Answer:A
Wednesday, March 10, 2010
GRE Math Problem 42
If 3a=b and 3c=d, then bd=
(A) 3ac
(B) 3a+c
(C) 6a+c
(D) 9ac
(E) 9a+c
Solution for GRE Math Problem 41:
Let’s build this sequence: 1, 1x3-1=2, 2x3-1=5, 5x3-1=14, 14x3-1=41, 41x3-1=122 – this is the smallest term greater than 100. It is greater than 120
Answer:A
(A) 3ac
(B) 3a+c
(C) 6a+c
(D) 9ac
(E) 9a+c
Solution for GRE Math Problem 41:
Let’s build this sequence: 1, 1x3-1=2, 2x3-1=5, 5x3-1=14, 14x3-1=41, 41x3-1=122 – this is the smallest term greater than 100. It is greater than 120
Answer:A
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